Answer: 1. AgF + CaCl2 = AgCl + CaF2
2. C2H4 +O2 = CO2 +H2O
3. K2S = K+S
4. O2 + Mg = MgO
5. Mg + AlBr3 = MgBr2 + Al
6.C2H6O + O2= CO2 + H2O
7.Li2SO4 + MgCl2= Li2SO4 + MgCl2
8.HCl + Zn= H2 + ZnCl2
Explanation:
Balance the equation
Write down your given equation.
Write down the number of atoms per each element that you have on each side of the equation.
Always leave hydrogen and oxygen for last.
If you have more than one element left to balance:
Add a coefficient to the single carbon atom on the right of the equation to balance it with the 3 carbon atoms on the left of the equation.
Balance the hydrogen atoms next.
Balance the oxygen atoms.
Answer:
5SiO2 + 2CaC2 = 5Si + 2CaO + 4CO2
Explanation:
balancing equations is a lot of trial and error. My strategy to approaching this equation was to get the O's balanced. After trying several combonations I found that I needed 10 O's on each side of the equation for the other elements to match up. After I balanced the O's, I balanced my C's to 4 on each side. Then I balanced my Ca's to have 2 on each side. And last but not least I balanced my Si to have 5 on each side.
Answer:
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have a good day :)
Explanation:
Answer:
Average atomic mass = 85.557 amu.
Explanation:
Given data:
Percent abundance of Rb-85 = 72.15%
Percent abundance of Rb-87 = 27.85%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (72.15×85)+(27.85×87) /100
Average atomic mass = 6132.75 + 2422.95 / 100
Average atomic mass = 8555.7 / 100
Average atomic mass = 85.557 amu.