Idk what is the answers so i see if i got then right
2m⁴ - 18n⁶
2(m⁴) - 2(9n⁶)
2(m⁴ - 9n⁶)
2(m⁴ - 3m²n³ + 3m²n³ - 9n⁶)
2[m²(m²) - m²(3n³) + 3n³(m²) - 3n³(3n³)]
2[m²(m² - 3n³) + 3n³(m² - 3n³)]
2(m² + 3n³)(m² - 3n³)
Answer:
correct option is C) 2.8
Step-by-step explanation:
given data
string vibrates form = 8 loops
in water loop formed = 10 loops
solution
we consider mass of stone = m
string length = l
frequency of tuning = f
volume = v
density of stone =
case (1)
when 8 loop form with 2 adjacent node is
so here
..............1
and we know velocity is express as
velocity = frequency × wavelength .....................2
= f ×
here tension = mg
so
= f × ..........................3
and
case (2)
when 8 loop form with 2 adjacent node is
..............4
when block is immersed
equilibrium eq will be
Tenion + force of buoyancy = mg
T + v × × g = mg
and
T = v × - v × × g
from equation 2
f × = f ×
.......................5
now we divide eq 5 by the eq 3
solve irt we get
so
relative density
relative density = 2.78 ≈ 2.8
so correct option is C) 2.8
1,000,000 = one million
Good Luck! :)
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