The heat energy released from a piece of wire or any other section of a circuit is:
Energy = (voltage between its ends) x (current through it) x (time it's been going)
Answer:
x2 = 0.99
Explanation:
from superheated water table
at pressure p1 = 0.6MPa and temperature 200 degree celcius
h1 = 2850.6 kJ/kg
From energy equation we have following relation
h2 = 2671.85 kJ/kg
from superheated water table
at pressure p2 = 0.15MPa
specific enthalpy of fluid hf = 467.13 kJ/kg
enthalpy change hfg = 2226.0 kJ/kg
specific enthalpy of the saturated gas hg = 2693.1 kJ/kg
as it can be seen from above value hf>h2>hg, so phase 2 is two phase region. so we have
quality of steam x2
h2 = hf + x2(hfg)
2671.85 = 467.13 +x2*2226.0
x2 = 0.99
The correct is 72 watt
We know that formula of power is
so putting the value of Voltage and Resistance in Formula of power so we get
What is Power?
Electric power is the rate at which an electric circuit transfers electrical energy per unit time.
Typically, electricity is generated by generators, but it can also be supplied by sources such as electric batteries. The electric power industry typically distributes it via an electric power grid to businesses and homes (as domestic mains electricity).
Transmission lines allow electric power to be delivered over long distances and used for high-efficiency applications such as motion, light, or heat. Electric charges are converted to other forms of energy when they pass through an electric potential difference (voltage).
To learn more about Power from the given link:
brainly.com/question/2333114
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Answer:
Explanation:
- The concept of gibb's free energy is applied in the problem. Mathematically from Gibb's free energy ; ΔG = ΔH - TΔS
- Entropy = ΔS = is the degree of disorderliness of the system.
- Since the enthalpy of vaporization is given ΔHvap = 38.0kJ/mol = 38000J/mol
- Also ΔSvap = 112.9J/mol.K
- Temperature of the experiment given = 75 degree celsius
calculate the boiling point of the solvent ; T = ΔHvap/ΔSvap
- T = 38000J/mol / 112.9J/mol.K
- = 335.57K , in celsius ; 335.57K - 273
the temperature calculated indicates that the solvent is not suitable for the experiment because its boiling point is lesser than the temperature at which the experiment want to be carried out.