The perimeter of the pentagon with apothem of 5cm is 28.87cm
<h3>How to calculate the perimeter of a pentagon</h3>
The sum of all the external sides of the pentagon is its perimeter.
First we need to calculate the half of one of its sides using the SOH CAH TOA
tan 30 = x/5
x = 5 tan 30
x = 2.89
One of the sides = 2(2.89) = 5.77 cm
Perimeter of th pentagon = 5(5.77) = 28.87
Hence the perimeter of the pentagon with apothem of 5cm is 28.87cm
Learn more on perimeter of pentagon here: brainly.com/question/11484726
Answer:
I did for you but I don't know you will understand my HANDWRITING or not .
:(
1. square base area= 25 inches
2. using the slanted 6.5
=1/2base , therefore 5/2=2.5 inches
3. then use pythagoras.... c=6.5, a=2.5
c^2=a^2 + b^2
(do this urself)
4. when u find what b is... that's the height of one of the triangle
base= 2.5 (look at step 2 if u don't understand this bit)
height=b (refer to step 3)
5. then work out the area of 1 triangle using that...
6. then have (the answer u work out in step 5 ) multiply 4
this will give u the area for the all of the 4 triangles...
7. Then add together the square based area in step 1..(25)
to the 4 triangular, area faces (i.e from step 6) - the total will be ur answer for the amount of cardboard!!
p.s don't forget the units!!!
Answer:
a) positive direction: t < 2s & t>6s ; negative direction: 2s < t < 6s
b) 7 m
c) 71 m
Step-by-step explanation:
Given:
v(t) = 3t^2 -24t +36 [0 , 7]
Find:
a) The value of time when particle is moving in positive direction:
The change in direction of the particle can be determined by v(t) > 0
Hence,
0 < 3t^2 -24t +36
0 < t^2 - 8t + 12
0 < (t - 2)*(t - 6)
t < 2s , t > 6s
The particle travels in positive direction in the interval t < 2s and t > 6s , While it travels in negative direction when 2s < t < 6s.
b) The displacement ds over the given interval [ 0 , 7 ]
ds = integral (v(t)).dt
ds = t^3 -12t^2 +36t
ds = 7^3 -12*7^2 +36*7
ds = 7 m
c) Total distance traveled in the interval:
Total distance= ds(0-2) + ds(2-6) + ds(6-7)
D = 2*(2^3 -12*2^2 +36*2) - 2*(6^3 -12*6^2 +36*6) + 7
D = 2*32 - 2*0 + 7
D = 71 m
