![x^{\frac{1}{2}} = \sqrt[2]{x}](https://tex.z-dn.net/?f=%20x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Csqrt%5B2%5D%7Bx%7D%20)
and ![3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}}](https://tex.z-dn.net/?f=%203%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Cfrac%7B1%7D%7B3%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%7D%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B2%5D%7B3%7D%7D%20)
so
and you rationalize denominator by multiplying numerator and denominatr by 
so that gives--
Your answer is 
Answer:
1) No
2) No
3) Yes
4) No
5) Yes
Step-by-step explanation:
All three sides must add with another to be greater than the last side (Not sure if that makes sense ._.)
Answer:
-3.8 - (7.2-10 3/8)
-3.8+(-7.2+10 3/8) this is the error, it's positive 10 3/8, not negative, then you should solve what's in the parentheses first
I simplified 10 3/8 into 83/8 and then 10.375
-3.8+(-7.2 + 10.375)
-3.8+ 3.175 = -0.625
7^2 = 6^2 + 9^2 - 2(6)(9)cos(m)
-68 = 2(6)(9)cos(m)
cos(m) = -0.6296
m = arcos ( -0.6296)
m = 129.0 degrees
Answer:
109/2 is the answer of your question . Use PEMDAS rule
