Here the two samples should be comparable .
The total number of cows in the farm = 200
the total number of cows giving milk = 150
the total number of cows in corral = 20
Suppose total number of cows giving milk in corral = x
The ratio of the total number of cows present to the total number of cows giving milk should be same in farm and corral
so : 200 = 20
------- -------
150 x
now we do cross multiplication :
200 x = 150* 20
200x = 3000
x= 3000/200
x= 15
SO we expect 15 cows in corral should be giving milk .
Answer : 15
Answer:
3.
Step-by-step explanation:
Implicit differentiation:
x^2 y + (xy)^3 + 3x = 0
x^2 y + x^3y^3 + 3x = 0
Using the product rule:
2x* y + x^2*dy/dx + 3x^2 y^3 + x^3* (d(y^3)/dx) + 3 = 0
2xy + x^2 dy/dx + 3x^2 y^3 + x^3* 3y^2 dy/dx + 3 = 0
dy/dx(x^2 + 3y^2x^3) = (-2xy - 3x^2y^3 - 3)
dy/dx= (-2xy - 3x^2y^3 - 3) / (x^2 + 3y^2x^3)
At the point (-1, 3).
the derivative = (6 - 81 - 3)/(1 -27)
= -78/-26
= 3.
Answer:
do you think you can write them in chat or copy n paste?? please because i can solve these but i need a beet look
Step-by-step explanation:
The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
<h3>How to find a sector area, and arc length?</h3>
For a sector that has a central angle of θ, and a radius of r;
The sector area, and the arc length are:
--- sector area
---- arc length
<h3>How to find the given sector area, and arc length?</h3>
Here, the given parameters are:
Central angle, θ = 160
Radius, r = 5 inches
The sector area is
So, we have:
Evaluate
A = 34.92
The arc length is:
So, we have:
L = 13.97
Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
Read more about sector area and arc length at:
brainly.com/question/2005046
#SPJ1
Answer:
3.125 ounces
Step-by-step explanation:
10/3.20=3.125
