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2 years ago

Find an equation for the nth term of the arithmetic sequence.

Mathematics

2 answers:

Sunny_sXe [5.5K]2 years ago

5 0

Answer:

asdop

Step-by-step explanation:

balandron [24]2 years ago

4 0

Answer:

an = 896 - 53(n - 1)

$a _{19} = l + (19 - 1) \times d \\ - 58= l+ 18d - - - (i) \\ \\ a _{21} = l + (21 - 1)d \\ - 164 = l + 20d - - - (ii) \\ (ii) - (i) : \: - 106 = 2d \\ d = - 53 \\ hence : l = - 58 - (18 \times - 53) \\ l = 896 \\ = > a _{n} = 896 + (n - 1) \times - 53 \\ a _{n} = 896 - 53 (n - 1)$

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Helga [31]

Answer:

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For questions 5a–5d, choose the the pair of numbers in which 3 is the GCF

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1 year ago

The point P(5, −4) lies on the curve y = 4/(4 − x).

dalvyx [7]

Answer:

Step-by-step explanation:

Slope refers to the steepness of the line.

Slope is equal to change in value of y divided by change in value of x.

The slope of the secant line is given by $\frac{f(x)-f(a)}{x-a}$ .

Given points are $P\left ( 5,-4 \right )\,,\,Q\left ( x,\frac{4}{4-x} \right )$

So, slope of the secant line is $\frac{\frac{4}{4-x}+4}{x-5}=\frac{4+4(4-x)}{(x-5)(4-x)}=\frac{20-4x}{(x-5)(4-x)}=\frac{-4(x-5)}{(x-5)(4-x)}=\frac{-4}{4-x}=\frac{4}{x-4}$

(i) At x = 4.9,

$\frac{4}{4.9-4}=\frac{4}{0.9}=4.444444$

(ii) At x = 4.99,

$\frac{4}{4.99-4}=\frac{4}{0.99}=4.040404$

(iii) At x = 4.999,

$\frac{4}{4.999-4}=\frac{4}{0.999}=4.004004$

(iv) At x = 4.9999,

$\frac{4}{4.9999-4}=\frac{4}{0.9999}=4.0004$

(v) At x =5.1,

$\frac{4}{5.1-4}=\frac{4}{1.1}=3.636364$

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At x = 5.01,

$\frac{4}{5.01-4}=\frac{4}{1.01}=3.960396$

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$\frac{4}{5.001-4}=\frac{4}{1.001}=3.996004$

(viii) At x = 5.0001,

$\frac{4}{5.0001-4}=\frac{4}{1.0001}=3.9996$

(b)

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2 years ago

The sum a 8 and a number h is 12

Artyom0805 [142]

H would equal to 4 (8+4=12)

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2 years ago

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Please help me i know this might take a while but plz my teacher be buggin <br> Due today

trasher [3.6K]

Answer:

5) Part A: The rate of change, also known as the slope, is the "0.6x" part of the equation. It means that for every week the puppy is alive, x, that number is multiplied by 0.6 pounds.

Part B: The y-intercept is 4 pounds, which represents a puppy being 4 pounds at birth.

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Part D: y = 0.6x + 4

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18/0.6 = 0.6x/0.6

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It would take a puppy 30 weeks to reach 22 pounds.

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