It's not specified whether 1 is the 1st or 2nd roll: HOWER:
The 1st Roll is "1": P(odd sum/the 1st Roll is 1)
What is the sample space of all numbers starting with "1":
{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),} = 6
the couple of add sum=(1,2), (1,4), (1,6), =3
P(odd sum/ 1st is 1) = 3/6 =1/2
or in applying the formula:
P(odd sum/the 1st Roll is 1) =P(odd sum ∩ 1) / P(getting "1") it will give the same probability = 1/2
NOW if the 2nd Roll is "1", it 's still 1/2
Answer: 30/40, 25/40, 4/40
Step-by-step explanation: Using the Least Common Denominator, I looked at each multiple of each number to determine 40 as the least common denominator, and since we did 4 x 10 to get 40 in the first one, we do 3 x 10 in the first one as well making it 30/40. The second one we did 8 x 5 to get 40, making the numerator (top number) the product of 5 x 5 which is 25 making it 25/40. For the last one, I used 10 x 4 to get 40 meaning I would have to do 1 x 4 to get the numerator (top number) making it 4/40
12 multiplied by 12 equals 144.
Answer:
12x - 6
Step-by-step explanation:
8x - 3 + 4x - 3
12x - 6
x = - 2