-f - 5(2f - 3)
1. -5 * 2f = -10f
2. -5 * -3 = 15
3. -f - 10f + 15
4.Add like terms,
-f - 10f = -11f.
5.-11f + 15
Answer: -11f + 15
We know that both groups feed grass hay in the morning, so that's 100/100.
First group feeds alfalfa and grass in the evening
Second group feeds alfalfa and oat hay in the evening.
The estimated probability that horse owners feed grass hay the morning (AM) is 100%.
The estimated probability that horse owners feed alfalfa + oat hay in the pm is 28/100 or 28% (C)
Answer:
The correct answer is C.
Step-by-step explanation:
In order to solve this problem, you need to simplify the equation by using a natural log (ln). This will cancel out the e and make it easy to solve.
e^(2x + 5) = 4 ----> Take the ln
lne^(2x + 5) = ln(4) ------> Simplify
2x + 5 = ln(4) ------> Subtract 5
2x = ln(4) - 5 -----> Divide by 2
x = [ln(4) - 5]/2
Answer:
The answer is B
Step-by-step explanation:
Mean= 3
yell at me if im not right lol
Answer:
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Step-by-step explanation:
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