Six hundred thirty two and seven hundred forty five thousandths.
600 + 30 + 2 + .7 + .04 + .005
F(x,n,p)=C(n,x)p^x*(1-p)^(n-x)
n=9, p=0.8 =>
f(x,9,0.8)=C(9,x)0.8^x*(0.2)^(9-x)
The function f(x,9,0.8) is then calculated using the above formula
x f(x)
0 0.0000001 0.0000182 0.0002953 0.0027534 0.0165155 0.0660606 0.1761617 0.3019908 0.3019909 0.134218
Check Sum f(x), [x=0,9] = 1.0 ok
To determine the number of gallons of gasoline that is used, we need to know the rate of usage of gasoline. This rate would describe the number of gasoline in units of volume that is being used per distance in units of length. In this case, we need the rate in units of miles per gallon. From what is asked and the given values, we simply divide the rate to the the total distance that was traveled by the car. We calculate as follows:
Gallons of gasoline = 293 miles / 57 miles / gallon
Gallons of gasoline = 5.14 gallons
Therefore, about 5 gallons of gasoline was consumed by the hybrid car for a distance of 57 miles.
Answer:
2)
collect like terms
move the constant to the right hand side and change its sign.
Subtract the numbers
Divide both sides of the equation by 8
