The part of the triangles which are congruent according to the description are; segment AB and segment DE.
<h3>Which parts of the triangles are congruent?</h3>
It follows from the task content that the two triangles ABC and DEF have been established as congruent. On this note, it can be established that by the congruence theorem that corresponding sides which are congruent and whose ratios equal to a constant ratio are segments AB and segment DE.
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Assuming you mean whole numbers, 41 times 1 equals 41, or 1 times 41.
Answer:
Step-by-step explanation:
No. Each side must be less than the sum of the remaining two sides.
10 ≮ 5+1
Answer:
The diameter of the target is
Step-by-step explanation:
we know that
In this problem the distance from the center of an archery target to the outside edge of the target is equal to the radius of the target
so
Remember that
The diameter is two times the radius
substitute