Answer:
S={( 1 )}
Step-by-step explanation:
-3x²+6x+1=4
-3x²+6x+1-4=0
-3x²+6x-3=0
∆=b²-4.a.c
∆=(6)²-4.(-3).(-3)
∆=36-36
∆=0
x'=x"=-b/2a=-(+6)/2.(-3)=-6/-6=1
4(3-7x). Since there are 4 sides in a square, you multiply one length by 4 to get the perimeter. 4(3-7x) simplifys to 12-28x.
Answer:
1) 145°
2) 20°
3) x = 7 ; measurement of the missing angle = 24
Step-by-step explanation:
1) supplement = 180°, 180 - 35 = 145
2) complment = 90° , 90 - 70 = 20
3) the figure is a right angle so the measurement is 90°
66 + (4x-4) = 90
62 + 4x = 90
4x = 28
x = 7
4(7) - 4
28 - 4
= 24
Answer:
See detail below.
Step-by-step explanation:
A word of caution before getting to the actual problem: I believe there is an important set of brackets missing in the original post. The expression on the left hand side should be:
(cosxtanx-tanx+2cosx-2)/(tanx+2)
Without the brackets, it is left unclear whether the denominator is just tanx or tanx+2. I recommend to use brackets wherever any doubt could arise.
Now to the actual problem: \we can make the following transformations on the left hand side:
which is shown to be the same as the right hand side, which was to be shown.
Answer:
Since sine of all angles are always less than one, this shows there is no possible way to have an angle C. Thus it is impossible to have a triangle ABC with the given properties of side lengths b=3 inches and c= 5 inches to have angle B =45 degrees.
Step-by-step explanation:
In the attached drawing, each of the tic-marks are equal and
represent 1 inch each. The angle B has measure 45. We can
see by the arc that the line AC, which equals 3 inches, is
not long enough to reach the slanted side of the 45 angle.
Therefore triangle ABC is not possible. We can also show
by the law of sines that no triangle ABC with the given
properties in possible.