Tiger is a top predator in the jungles of Asia and the goldfish is a small species of fish selectively bred in China and they are not at all related.
All living things have the same way of transferring genetic information, trough the DNA molecule. Genetic analyses showed that the last common ancestor (LUCA) of all organisms on Earth has lived 3,5 billion years ago. After that, all living things diverged into separate groups. Tigers and goldfish both are animals and have a common ancestor. Tigers may be in a close relationship with other big cats like lions and cheetahs, but they all have a common ancestor with the goldfish since all vertebrates have a common ancestor that was an ancient fish species.
It's some change in the conditions around the organism, which the organism can detect and respond to. A change in temperature, more light, or something physically poking the organism are examples.
Answer:
Suppose that at a given point along a capillary, the following forces exist: Capillary hydrostatic pressure (HPc) = 30 mmHg Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg Capillary colloid osmotic pressure (OPc) = 25 mmHg Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg. The net filtration pressure at this point in the capillary is <u>7mmHg.</u>
Explanation:
Capillary hydrostatic pressure (HPc) = 30 mmHg
Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg
Capillary colloid osmotic pressure (OPc) = 25 mmHg
Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg
Net filtration pressure= hydrostatic pressure gradient - Oncotic pressure gradient
Hydrostatic pressure gradient = Capillary hydrostatic pressure - Interstitial hydrostatic pressure = 30mmHg - 0 mmHg = 30 mmHg
Oncotic pressure gradient = Capillary colloid osmotic pressure - Interstitial fluid colloid osmotic pressure =25 - 2 = 23 mmHg
Net filtration pressure= hydrostatic pressure gradient - Oncotic pressure gradient = 30 mmHg - 23 mmHg = 7 mmHg.
Hence, The net filtration pressure at this point in the capillary is <u>7mmHg.</u>
Endangered Species Act of 1973
I think the answer is c because each polymer has 1 monomer