Answer:
The distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
Explanation:
Given;
speed of the faster car, v₁ = 60 mi/h
speed of the slower car, v₂ = 55 mi/h
Let the distance traveled by the faster car when it is 15 mins ahead of the slower car = x miles
Note: divide 15 mins by 60 to convert to hours for consistency in the units.
Therefore, the distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
The combination of all of the forces acting on object is net force.
Answer:
The value is
Explanation:
From the question we are told that
The mass of matter converted to energy on first test is
The mass of matter converted to energy on second test
Generally the amount of energy that was released by the explosion is mathematically represented as
=>
=>
Answer:
0.027 J
Explanation:
The formula of the potential energy in electrostatic (U) is
The values given in the question are
Charge : q =
Electric Field strength : E =
Distance : d is 0.030 m
Insert in the formula , will give us
Further solving it
Which is the required answer.
Thanks
1.7 x 10^2 N
or 166 N
First you find the vertical component of the weight, which is 9.8*40, (g*m), which is 392 N. You then find the angle between that and the slope, which is 90-25, which is 65. You then multiply the vertical weight by cos(65), to find the component of that that is parallel to the slope. You get 165.666 N