Just did a specific one of these; let's do the general case.
The point nearest the origin is (a,b).
The line from the origin through the point is
The line we seek is perpendicular to this one. We swap the coefficients on x and y, negating one, to get the perpendicular family of lines. We set the constant by plugging in the point (a,b):
That's standard form; let's plug in the numbers:
I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,
So,
So,
Hope this helps you!
Answer:
A.
Step-by-step explanation:
The x-intercepts are the points where the x value is zero. In this case, to find the "zeros" of the function, set each factor to zero. x-5 -> x=5. x-6 -> x=6. x+4 -> x=-4.
Answer:
56 total units
Step-by-step explanation:
Here is what the plane would look like if the figure and points were drawn.
Answer:
y + 2 = -3(x - 7)
Step-by-step explanation:
Write the equation using the point slope form 
. Substitute m = -3 and (7,-2).
