A car dealership recently started tracking the number of cars sold each month based on the number of commercials aired on TV tha
t month. The scatter plot shows this data. A line of best fit has been drawn.
The equation for the line of best fit is shown.
y = 3.33x + 13.5
Based on the equation for the line of best fit, about how many cars will the dealership sell in a month if they air 14 commercials that month?
A. 53 cars
B. 60 cars
C. 72 cars
D. 85 cars
The equation for the line of best fit is shown.
y = 3.33x + 13.5
Based on the equation for the line of best fit, about how many cars will the dealership sell in a month if they air 14 commercials that month?
A. 53 cars
B. 60 cars
C. 72 cars
D. 85 cars
2 answers:
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The term that has a degree of 8 is -2x³y⁵
<h3>How to find the degree of a polynomial?</h3>The polynomial above is a monomial. A monomial is a polynomial with a single term.
Therefore, the degree of a monomial is the sum of the exponents of all its variables.
In other words, a monomial is a number, a variable or a product of a number and a variable where all exponents are whole numbers.
Hence, the term with degree of 8 is -2x³y⁵
Degree = 0 + 3 + 5 = 8
learn more on degree here: brainly.com/question/14939467
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Answer:
Step-by-step explanation:
it's obvious that 3·3·3·3=81
or you can do the prime factorization of 81
Answer:
(x, y) = (5, -4)
Step-by-step explanation:
The second equation gives you an expression for x that can be substituted into the first equation.
(2y +13) -3y = 17 . . substitute for x in the first equation
-y = 4 . . . . . . . . . . . subtract 13 and simplify
y = -4
x = 2(-4) +13 = 5 . . . use the second equation to find the value of x
The solution is (x, y) = (5, -4).
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<em>Additional comment</em>
When faced with a system of linear equations, the first step is to look at them and observe where the variable terms are, and any relationships between coefficients. Several options are generally open to you for solving the equations. Methods generally taught first are ...
- substitution
- elimination
<em>Substitution</em> is handy when one of the variables or variable terms can be written (easily) in terms of the other variable. <em>Elimination</em> is handy when some simple multiple of one of the equations can be added to the other equation to cancel one of the variable terms (eliminate it).
Other available methods include matrix methods, Cramer's rule, and graphing. Working knowledge of all of these methods will help you identify the one that will be easiest to use in any given situation.
The availability of calculators able to use these methods greatly simplifies the task of finding a solution. It is simply a matter of entering the equations in the appropriate form.
One of my favorites is the graphing calculator, which only requires you type in the given equations and click on the solution point to find its coordinates.
