Answer:4
Step-by-step explanation:
Alternate angles are equal, therefore the other angle will be 4 since they are alternate
All these equations are in the form of ax^2 + bx + c = 0, where a, b, and c are some numbers. the discriminants of equations like this are equal to b^2 - 4ac. if the discriminant is negative, there are two imaginary solutions. if the discriminant is positive, there are two real solutions. if the discriminant is 0, there is one real solution.
<span>x^2 + 4x + 5 = 0
</span>b^2 - 4ac
4^2 - 4(1)(5)
16-20
-4, two imaginary solutions.
<span>x^2 - 4x - 5 = 0
</span>b^2 - 4ac
(-4)^2 - 4(1)(-5)
16 + 20
36, two real solutions.
<span>4x^2 + 20x + 25 = 0
</span>b^2 - 4ac
20^2 - 4(4)(25)
400 - 400
0, one real solution.
Answer:
The answer would be c
Step-by-step explanation:
Answer:
and
Step-by-step explanation:
First make all the fractions into improper fractions
After doing that put them back into the problems
Problem 1)
÷ 
, plug in the improper fractions
÷ 
to divide, you need to flip the second fraction and multiply
· 
= 
then reduce
Problem 2)
÷ 
Plug in improper fraction
÷
Then flip second fraction and multiply
· 
Multiply
Reduce, or make it a mixed number
