14.9. this is because 8 is in the tenth place, and the next number is five. for numbers greater than 4, you round up, for four or less, you stay the same.
Answer:
1.No, 143 is not a prime number. The list of all positive divisors the list of all integers that divide 143 is as follows: 1, 11, 13, 143. To be 143 a prime number, it would have been required that 143 has only two divisors, itself and 1.
2.Since the polynomial can be factored, it is not prime.
5/6 would be the best answer beside the other 2 choices that you have
Answer:
(6.8, 1.3)
Step-by-step explanation:
<u>Given</u>:
A(-3, -5), B(11, 4)
<u>Find</u>:
P such that AP/AB = 7/10
<u>Solution</u>:
Using the desired relation, we have ...
(P -A)/(B -A) = 7/10
10(P -A) = 7(B -A) . . . . . multiply by 10(B-A)
10P = 7B +3A . . . . . . . . add 10A to both sides
10P = 7(11, 4) +3(-3, -5) = (77 -9, 28 -15) = (68, 13)
P = (68, 13)/10 = (6.8, 1.3)
The point 7/10 of the way from A to B is (6.8, 1.3).
Answer: option B
Step-by-step explanation:
-4, 1, 3
