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2 years ago

The sides of two cubes are in the ratio 2:1. What is the ratio of their volumes ?

Mathematics

1 answer:

olasank [31]2 years ago

5 0

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Answer:

we know that, Volume of cube=a³

Let volume of 1st cube be 2x with side a and other be x with side A (according to given ratio)

Step-by-step explanation:

ATQ: 2x=a³ and, x=A³

a=³√2x and, A=x

we know that, surface area of cube is 6a²

Thus, surface area of 1st cube = 6(³√2x)²

= 6³√4x²

Surface area of 2nd cube=6(x)²=6x²

Ratio of S.A=(6³√4x²)÷(6x²)

Ratio of S.A=³√4:1

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The answer is
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To rationalize the denominator, we multiply by the conjugate. The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign. The conjugate of -2-i is -2+i:

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\\=\frac{-6i+3i^2}{4-2i+2i-i^2}
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