Answer:
Explanation:
The answers are all written in the attachment below. Pardon the writing
Answer:
Explanation:
THE CORECT QUESTION
A 50.0 mL solution of 0.127 M KOH is titrated with 0.254 M HCl. Calculate the pH of the solution after the addition of each of the given amounts of HCl.
SOLUTION
Get the concentration of the HCl first using titration formula
CA X V A / CB VB = NA/ NB
Equation of reation; KOH + HCl => KCl + H2O
CA = 0.254 M
CB = 0.127
VA = 1/0.254 = 3.937
CA (after the addition) = 0.127 x 50 / 3.937
= 1.612 M
But pH = - Log[hydrogen ion]
= -log 1.612
=
Answer: D) 1 lone pair, square pyramidal
Explanation:
Formula used :
where,
V = number of valence electrons present in central atom = 7
N = number of monovalent atoms bonded to central atom = 5
C = charge of cation = 0
A = charge of anion = 0
Now we have to determine the hybridization of the molecule.
Bond pair electrons = 5
Lone pair electrons = 6-5 = 1
The number of electrons are 6 that means the hybridization will be and the electronic geometry of the molecule will be octahedral .
But as there are five atoms around the central iodine atom, the sixth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be square pyramidal.
Answer:
protons
Explanation:
i remember it as positive protons
neutral neutrons and
negetive electrons
5.18mL i hope this helps i hope this does to!