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2 years ago

The question is in the picture. (Alegbra 1)

Mathematics

2 answers:

morpeh [17]2 years ago

6 0

Answer:

Step-by-step explanation:

4/5a*3/2a^2

4*3/5a*2a^2

12/10a^3

6/5a^3

therefore ur answer is 6/5a^3

Varvara68 [4.7K]2 years ago

6 0

Answer:

option 3

Explanation :

$\frac{4}{5a} \cdot \frac{3}{2a^2} = \frac{12}{10 a^3} = \frac{6}{5a^3}$

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Step-by-step explanation:

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Read 2 more answers

The probability of winning a certain lottery is 1/77076 for people who play 908 times find the mean number of wins

Alex73 [517]

The mean is 0.0118 approximately. So option C is correct

<h3><u>Solution:</u></h3>

Given that , The probability of winning a certain lottery is $\frac{1}{77076}$ for people who play 908 times

We have to find the mean number of wins

$\text { The probability of winning a lottery }=\frac{1}{77076}$

Assume that a procedure yields a binomial distribution with a trial repeated n times.

Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.

$n=908, \text { probability } \mathrm{p}=\frac{1}{77076}$

$\text { Then, binomial mean }=n \times p$

$\begin{array}{l}{\mu=908 \times \frac{1}{77076}} \\\\ {\mu=\frac{908}{77076}} \\\\ {\mu=0.01178}\end{array}$

Hence, the mean is 0.0118 approximately. So option C is correct.

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2 years ago

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Inessa [10]

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Step-by-step explanation:

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