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2 years ago

Which one represents a line which is parallel to the line y=-7x-4

Mathematics

1 answer:

Mekhanik [1.2K]2 years ago

3 0

Answer:

Any linear equation of the slope-intercept form y =7x/4+ b will be parallel to y=7x/4, since the slope of 7/4 will be the same for all such lines

Step-by-step explanation:

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After diving 86 feet below the surface, a diver ascends at 4 feet per minute. After 12 minutes pass, where is the diver located

Gemiola [76]

One possible way:
-86+(4*12)=-38
-86 is the number where the diver is. 86 feet below the surface.
4*12 is the total number of feet he has ascended in 12 minutes.
Because he is ascending, so you add 4*12 (or 48) to -86.
The answer is -38, meaning he's 38 feet below the surface.

The diver is now 38 feet below the surface.

Hope this helps.

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2 years ago

A covered water tank is in the shape of a cylinder. The tank has a 28-inch diameter and a height of 66 inches. To the nearest sq

ad-work [718]

$A = 2 \pi rh + 2 \pi r ^{2}$
$r = \frac{1}{2} (28) = 14$
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2 years ago

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Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$

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1 year ago

two hundred tickets for the school play were sold. tickets cost $2 for students and $3 for adults. the total amount collected wa

Gre4nikov [31]

A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.

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2 years ago

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kakasveta [241]

Answer:

About $0.2708 per unit ' each can '.

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3 years ago

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