Answer:
Results are below.
Step-by-step explanation:
Giving the following information:
Monthly deposit= $100
Interest rate= 0.06/12= 0.005
Number of periods= 12*5= 60 months
<u>a)</u>
<u>To calculate the future value, we need to use the following formula:</u>
FV= {A*[(1+i)^n-1]}/i
A= monthly deposit
FV= {100*[(1.005^60) - 1]} / 0.005
FV= $6,977
b) <u>If the deposit is at the beginning of the month, the interest is compounded one more period</u>. We need to use the following formula:
FV= {A*[(1+i)^n-1]}/i + {[A*(1+i)^n]-A}
FV= 6,977 + {[100*(1.005^60)] - 100}
FV= 6,977 + 35
FV= $7,012
Answer:
Solve by adding or subtracting like terms. (Ex. 2k + 4k = 6k; 9 + 7 = 16)
- 6k + 7k = 1k = k
(7 - 6 = 1)
12r - 8 - 12 = 12r - 20
(8 + 12 = 20 but sign is negative) 12r will stay the same because there are no terms with a letter r.
n - 10 + 9n - 3 = 9n + n - 10 - 3 = 10n - 10 - 3 = 10n - 13
(n = 1 so 9 + 1 = 10; 10 + 3 = 13 but negative sign)
- 4x - 10x = 14x
(10 + 4 = 14)
- r - 10r = 11r
(r = 1 so 10 + 1 = 11)
Answer:
number = 24
Step-by-step explanation:
3 x 8 = 24
24 / 3 = 8
Using the given table:
a) the average rate of change is 32.5 jobs/year.
b) the average rate of change is 12.5 jobs/year.
<h3>
How to find the average rate of change?</h3>
For a function f(x), the average rate of change on an interval [a, b] is:
a) The average rate of change between 1997 and 1999 is:
So the average rate of change is 32.5 jobs/year.
b) Now the interval is 1999 to 2001.
The rate this time is:
So the average rate of change is 12.5 jobs/year.
If you want to learn more about average rates of change:
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Answer:
(3, 5)
Step-by-step explanation:
Point (3, -5) is 5 units below the x-axis.
After it is reflected, it will be 5 units above the x-axis.
Answer: (3, 5)