Answer:
d. pxp +2pq
Explanation:
The formula for genotype frequency for a population in Hardy-Weinburg equilibrium is as under:
p² + 2pq + q² = 1
where, p = dominant allele
q = recessive allele
Here,
p² represents frequency of homozygous dominant genotype
2pq represents frequency of heterozygous genotype
q² represents frequency of homozygous recessive genotype
Also, although the genotypes p² & 2pq are different from each other yet phenotypically they both will collectively produce dominant trait i.e. free ear lobes not attached earlobes. So the term "p² + 2pq or pxp + 2pq" represents the frequency of the individuals who show the dominant phenotype in this particular population. Dominant phenotype will comprise 75% of the population.
Answer:
pyruvate and acetyl-CoA
Explanation:
The first step of respiration reactions is glycolysis. When glucose is broken down in glycolysis, the first molecule that is produced is pyruvate. If pyruvate continue to aerobic respiration, it must enter the matrix of mitochondria and be oxidised to Acetly Co-A.
Answer:
Afferent arterioles are a group of blood vessels that supply blood to glomerulus in nephron while afferent arteriole brings back blood from glomerolus.
Answer:
Inorganic fertilizers are not entirely composed of the nutrients needed by the plants. It also contains salts and other compounds. These are not absorbed by the plants so they are left behind in the soil and build up over time.