900=300(1+0.058)^t divide each side by 300
3=1.059^t
Log(3)=t*log(1.058)
T=log(3)/log(1.058)
T==19.5 years
Answer:
21,637
Step-by-step explanation:
You can just use a caculator- Or simple multiplication by putting it on top of eachother.
You can do this many ways,just multiply with pen and paper,put 250 on top,and 85 on bottom which is 21,250,the add from there!
Hope I helped!!
Answer:
225.78 grams
Step-by-step explanation:
To solve this question, we would be using the formula
P(t) = Po × 2^t/n
Where P(t) = Remaining amount after r hours
Po = Initial amount
t = Time
In the question,
Where P(t) = Remaining amount after r hours = unknown
Po = Initial amount = 537
t = Time = 10 days
P(t) = 537 × 2^(10/)
P(t) = 225.78 grams
Therefore, the amount of iodine-131 left after 10 days = 225.78 grams