Answer:
30.17feet high
Step-by-step explanation:
Given the following
the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)
angle of elevation = 38°
Required
Height of the flagpole (opposite)
Using the SOH CAH TOA identity
Sin theta = opposite/hypotenuse
Sin 38 = H/49
H = 49sin38
H = 49(0.6157)
H = 30.17feet
Hence the flagpole is 30.17feet high
Answer:
the answer is RS=x+5
if I am right mark it as brianliest
{-2x-5y=13
<u>{2x-5y=17 </u>(+)
<em /> -2x+2x-5y-5y=13+17
-10y=30 /:(-10)
y=-3
2x-5y=17
2x-5*(-3)=17
2x+15=17
2x=2
x=1
<em>Solution: (1; -3)</em>
Answer:
1360
Step-by-step explanation:
there are 1200 seconds in 20 minutes. if Ella can do 17 jumps in 15 seconds, you would divide 1200 by 15 (which equals 80) because that would be the number of 15 seconds in 20 minutes. then you would divide 80 by 17, which gives you your final answer of 1360 jumps in 20 minutes.
Answer:
l=26
w=20
Step-by-step explanation:
l-6=w
2l+2w=92
2l+2(l-6)=92
2l+2l-12=92
4l=104
l=26
(26)-6=w
w=20
