Answer:
For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.
Step-by-step explanation:
The problem states that the monthly cost of a celular plan is modeled by the following function:
In which C(x) is the monthly cost and x is the number of calling minutes.
How many calling minutes are needed for a monthly cost of at least $7?
This can be solved by the following inequality:
For a monthly cost of at least $7, you need to have at least 100 calling minutes.
How many calling minutes are needed for a monthly cost of at most 8:
For a monthly cost of at most $8, you need to have at most 110 calling minutes.
For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.
An=3*(4^(n-1)) is the explicit
the recursive is <span>t_n = 4 * t_(n-1)</span>
Answer:
we need the question
Step-by-step explanation:
No 9.717 is greater than 9.707 because 9.717 would be seven hundred seven thousandths and 9.717 would be seven hundred seven teen hundredths.
14.50 x 2 (2 1/2 hours = 1 hour) = $29.00 + $14.50 (for another 1/2 an hour) = $43.50. Then, divide 14.50 in half for the other 15 minutes that weren't accounted for yet, so: $14.50/2 = $7.25 then add it to our previous total: $43.50 + $7.25 = $50.75 is your answer :) Hope I helped