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2 years ago

Can you help me with this question please

Mathematics

1 answer:

shtirl [24]2 years ago

4 0

Answer:

6 for $1.26 is better

Step-by-step explanation:

$1.26/6 = $0.21 per can

$1.98/9 = $0.22 per can

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Help ne with this math

stira [4]

The answer is A,E,G,L,D,and H.

You can check this by doing this:

This is for A

16*4=84

12*7=64

84+64=148

6 0

2 years ago

The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will

lakkis [162]

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

$V(t) = 14651(0.81)^{t}$

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

$V(t) = 14651(0.81)^{t}$

$(0.81)^t = \frac{V(t)}{14651}$

$\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}$

$t\log{(0.81)} = \log{(\frac{V(t)}{14651})}$

$t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}$

(a) $8000

V(t) = 8000

$t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9$

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

$t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2$

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

$t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7$

The car will be worth $1000 after 12.7 years.

5 0

2 years ago

PLEASE HELP! BRAINLIEST!!!!!!! PLEASE

Gnesinka [82]

Hello!

First you have to find the volume of the cylinder

To find the volume of a cylinder you use the equation

$V = \pi r^{2} h$

V is volume
r is radius
h is height

Put in the values you know and 3.14 for pi

$V = 3.14 * 3^{2} * 7$

Square the number

V = 3.14 * 9 * 7

Multiply

V = 197.82
------------------------------------------------------------------------------------------------------
Next you find the volume of the sphere

To find the volume of a sphere you use the equation

$V = \frac{4}{3} \pi r^{3}$

V is volume
r is radius

Put in the values you know and 3.14 for pi

$V = \frac{4}{3} * 3.14 * 3^{3}$

Cube the number

$V = \frac{4}{3} * 3.14 * 27$

Multiply

V = 113.04
------------------------------------------------------------------------------------------------------
Finally you subtract the two volumes from each other

197.82 - 113.04 = 84.78
------------------------------------------------------------------------------------------------------
The answer is C)84.78

Hope this helps!

7 0

2 years ago

Read 2 more answers

2.8, 3.4, 4.0, 4.6, . . . Write an equation for the nth term of the arithmetic sequence. Then find a50.

vova2212 [387]

Answer:

a_n = 2.2 + 0.6 n

a_50 = 32.2

Step-by-step explanation:

What's the common difference of this series?

$a_1 = 2.8$

$a_2 = 3.4$

Common difference = $a_2 - a_1 = 3.4 - 2.8 = 0.6$ .

Expression for the nth term:

$a_n = a_1 + (n - 1) \cdot\text{Common Difference} \\\phantom{a_n } = 2.8 + 0.6 \; (n-1) \\\phantom{a_n} = 2.8 + 0.6 \; n - 0.6\\\phantom{a_n} = 2.2 + 0.6\; n$

n = 50 for the fiftieth term. Therefore

$a_{50} = 2.2 + 0.6 \times 50 = 32.2$ .

6 0

2 years ago

2[3(4^2 +1)] - 2^3.

Sav [38]

Answer:

Step-by-step explanation:

Do parentheses first, exponents inside them first. 4^2 = 16, + 1 is 17, then multiply by the 3 outside to get 51, then multiply by the 2 outside that to get 102, - 2^3 which is -8 = 94

7 0

2 years ago