293 tens and 4 ones
<em>Explanation:
</em>If you have 293 tens you have 2930 already.
293*10 = 2930
Now you are only missing 4,
4*1 = 4
so you can use 4 ones
2x+10y-2.8x-5.2y+16=
-0.8x+4.8y+16
<span>Let be A= 6x6 − x3y4 − 5xy5 and B= 4x5y + 2x3y4 + 5xy5
and when we do their difference, it is A - B =
6x6 − x3y4 − 5xy5 -( 4x5y + 2x3y4 + 5xy5)=6x6 − x3y4 − 5xy5 - 4x5y - 2x3y4 - 5xy5 = 6x6 - x3y4 - 2x3y4 - 5xy5 -4xy5 -5xy5=6x6 - 3x3y4 -14xy5, so the final solution is A - B =6x6 - 3x3y4 -14xy5, the degree of this is equal to the degree of - 3x3y4, and it is 3+4=7, the answer is
The difference has 3 terms and a degree of 7.</span>
A. The range is equal to the highest value minus the lowest value. Since the table given in part A is already in terms of range, then there is no need for a solution. The range of temperature for each month is as it is.
B. For this question, find the largest value which would represent the all-time high. That would be on February at 95°F. The lowest value would also represent the all-time low. That would be on July at 50°F.
C. The range of part B is just the difference of the all-time high and all-time low temperatures.
Range = 95°F - 50°F = 45°F
Answer: The inverse of the linear function f(x)=2x+1 is f^(-1) (x) = (1/2)x-1/2
Solution
f(x)=2x+1
y=f(x)
y=2x+1
Isolating x: Subtracting 1 both sides of the equation:
y-1=2x+1-1
y-1=2x
Multiplying both sides of the equation by 1/2:
(1/2)(y-1)=(1/2)2x
(1/2)y-1/2=x
x=(1/2)y-1/2
Changing "x" by "f^(-1) (x)" and "y" by "x":
f^(-1) (x) = (1/2)x-1/2
