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2 years ago

5

Michelle had 600 fish to feed the dolphins in a zoo. Each dolphins ate the same number of fish. There are 9 dolphins in all. How

many fish did Michelle have left?

1 answer:

Juli2301 [7.4K]2 years ago

5 0

Answer:

each dolphins eat 600÷9=66.67

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Step-by-step explanation:

First one is 200 dollars for insurance which will be the constant and 15 dollars an hour which means the equation will be;

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Please help me solve -6 = 14 - z/3

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2 years ago

Read 2 more answers

Find the volume of the cone

irina1246 [14]

Answer:

The volume of the cone is 12936 cubic mm.

Step-by-step explanation:

Given

Circumference of base = 132 mm

Height of the cone = 28 mm

Solution

Formula of circumference = $2\pi r$ = 132 mm

$\therefore\ r= \frac{132}{2 \pi } = 21 mm$

Now volume of cone = $\frac{1}{3} \times\pi \times r^{2} \times h$

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2 years ago

Statistics show that about 42% of Americans voted in the previous national election. If three Americans are randomly selected, w

MrRa [10]

Answer:

19.51% probability that none of them voted in the last election

Step-by-step explanation:

For each American, there are only two possible outcomes. Either they voted in the previous national election, or they did not. The probability of an American voting in the previous election is independent of other Americans. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

42% of Americans voted in the previous national election.

This means that $p = 0.42$

Three Americans are randomly selected

This means that $n = 3$

What is the probability that none of them voted in the last election

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.42)^{0}.(0.58)^{3} = 0.1951$

19.51% probability that none of them voted in the last election

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2 years ago