The question is incomplete, complete question is:
Study this chemical reaction:
Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.
Oxidation:
Reduction:
Answer:
Oxidation taking place in given reaction :
Reduction taking place in given reaction;
Explanation:
Redox reaction is defined as the reaction in which oxidation and reduction reaction occur side by side.
Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
In the given reaction, iron(II) ions are getting reduced and zinc metal is getting oxidized to zinc(II) ions.
Oxidation :
Reduction ;
Explanation:
Quite a number of properties varies across a period. Some remains constant whereas others decreases.
As one moves from left to right;
- The energy level remains the same.
- The ionization energy increases progressively as a result of increasing nuclear charge.
- Electron affinity increases from left to right.
- Electronegativity increases.
- Electropositivity decreases.
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It took him 0.5 hrs to zoom over to Fat James’s house
Answer:
pH = 11.95≈12
Explanation:
Remember the reaction among aqueous acetic acid () and aqueous sodium hydroxide (NaOH)
First step. Need to know how much moles of the substances are present
= 0.0025 mol NaOH
0.003 mol NaOH * / 1 mol NaOH = 0.003 mol CH_3COOH[/tex]
NaOH is in excess. Now, how much?
0.003 mole NaOH - 0.0025 mole NaOH = 0.0005 mole NaOH
Then, that amount in excess would be responsable for the pH.
Third step. Know the pH
Remember that pH= -log[H+]
According to the dissociation of water equilibrium
Kw=[H+]*[OH-]= 10^(-14)
The dissociation of NaOH is
NaOH ->
Now, concentration of OH^{-}[/tex] would be given for the excess of NaOH.
[OH-]= 0.0005 mole / 0.055 L = 0.00909 M
Careful: we have to use the total volumen
Les us to calculate pH
The suffix -ene tells that there is a double bond present in the molecule, and the 2 tells where in the molecule the bond is located. The molecule looks like this:
CH3-CH=CH-CH3
-ane indicates single bonds
-ene indicates at least one double bond
-yne indicates at least one triple bond