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2 years ago

7

I forgot how to do this. please give me a example on how i do this thank u

1 answer:

nydimaria [60]2 years ago

4 0

Answer:

$t \in \mathrm {R}$

Step-by-step explanation:

$2t + 6 = 2(t + 3)$

$2t + 6 = 2t + 6$

$2t + 6 - 2t = 2t - 6 - 2t$

$6 = 6$

$t \in \mathrm {R}$

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What is the slope of a line perpendicular to the line whose equation is 4x−10y=404x−10y=40. Fully simplify your answer.

Anna007 [38]

Answer:

$- \frac{5}{2}$

Step-by-step explanation:

4x -10y= 40

Let's rewrite this equation in the slope-intercept form (y= mx +c) so that we can obtain it's slope.

10y= 4x -40

Divide both side by 10:

$y = \frac{2}{5} x - 4$

The product of the gradients of perpendicular lines is -1.

⅖(gradient of line)= -1

Gradient of perpendicular line

$= - 1 \div \frac{2}{5}$

$= - 1 \times \frac{5}{2}$

$= - \frac{5}{2}$

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2 years ago

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A person starts driving and travels 3 km east to a store. The person then turns around and travels 1 km west to another store. F

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2 years ago

Multiply (2a-5)(4a-7) Simplify your answer

Pie

$(2a - 5)(4a - 7)$

$2a(4a - 7) - 5(4a - 7)$

$8 {a}^{2} - 14a - 20a + 35$

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2 years ago

Read 2 more answers

What is the equation for

WARRIOR [948]

The equation of a line that is perpendicular to the given line is y = –4x – 16.

Solution:

The equation of a line given is y = 0.25x – 7

Slope of the given line( $m_1$ ) = 0.25

Let $m_2$ be the slope of the perpendicular line.

Passes through the point (–6, 8).

<em>If two lines are perpendicular then the product of the slopes equal to –1.</em>

$\Rightarrow m_1 \cdot m_2=-1$

$\Rightarrow 0.25\cdot m_2=-1$

$\Rightarrow m_2=\frac{-1}{0.25}$

$\Rightarrow m_2=-4$

Point-slope intercept formula:

$y-y_1=m(x-x_1)$

$x_1=-6, y_1=8$ and $m=-4$

Substitute these in the formula, we get

$y-8=-4(x-(-6))$

$y-8=-4(x+6)$

$y-8=-4x-24$

Add 8 on both sides of the equation.

$y-8+8=-4x-24+8$

$y=-4x-16$

Hence the equation of a line that is perpendicular to the given line is

y = –4x – 16

5 0

2 years ago