Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac
there are 3 basic cases of what happens for different discriminants
1. if the discriminant is less than 0, then there are no real zeroes
2. if the discriminant is 0, then it has 1 zero
3. if the discriminant is greater than 0, it has 2 zeroes
so given
0=3x^2-7x+4
a=3,b=-7,c=4
thus the discriminant is (-7)^2-4(3)(4)=49-48=1
the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0
the answer is the equation has two zeroes because the discriminant is greater than 0
Step-by-step explanation:
Answer:
-5.4c
Step-by-step explanation:
We're combining two "like" terms here.
It may make the problem easier to visualize if we write one of these terms over the other, as follows:
-2.6c
- 2.8c
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Adding, we get:
-2.6c
- 2.8c
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- 5.4c (answer)
Answer:
second quadrant
Step-by-step explanation:
(x, y ) → (x - 5, y + 3 ) means subtract 3 from the original x- coordinate and add 3 to the original y- coordinate.
(- 3, - 2 ) ← in third quadrant
→ (- 3 - 5, - 2 + 3) → (- 8, 1 ) ← in second quadrant
A) 25% = 25/100 = 0.25
b) 18% = 18/100 = 0.18
c) 40% = 40/100 = 0.40
d) 2% = 2/100 = 0.02
e) 0.15% = 0.15/100 = 0.0015
Answer:
C and D
Step-by-step explanation:
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