Methanol is prepared by reacting Carbon monoxide and Hydrogen gas,
CO + 2 H₂ → CH₃OH
Calculating Moles of CO:
According to equation,
32 g (1 mole) of CH₃OH is produced by = 1 Mole of CO
So,
3.60 × 10² g of CH₃OH is produced by = X Moles of CO
Solving for X,
X = (3.60 × 10² g × 1 Mole) ÷ 32 g
X = 11.25 Moles of CO
Calculating Moles of H₂:
According to equation,
32 g (1 mole) of CH₃OH is produced by = 2 Mole of H₂
So,
3.60 × 10² g of CH₃OH is produced by = X Moles of H₂
Solving for X,
X = (3.60 × 10² g × 2 Mole) ÷ 32 g
X = 22.5 Moles of H₂
Result:
3.60 × 10² g of CH₃OH is produced by reacting 11.25 Moles of CO and 22.5 Moles of H₂.
Answer: The new volume of cake is 1.31 mL.
Explanation:
Given: 
= 0.20 mL, 
= ?, 
Formula used to calculate new volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the new volume of cake is 1.31 mL.
I believe it forms an anion that has a larger radius.
Answer:
The Answer is gonna be behavior that is simple, untaught, and born knowing:3
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