Since K3 is greater than 1, the reaction is thermodynamically favorable.
Data;
- FeF2 is in an acidic solution
- K2 > 1 is thermodynamically favorable
- k3 > 1 is not thermodynamically favorable
- K1<1 is not thermodynamically favorable
<h3>Hess Law</h3>
This states that the heat change in a given chemical reaction is the same irrespective of the number of process in which the reaction is effected.
Using Hess Law;
substituting this using Gibbs law,
Since K3 is greater than 1, the reaction is thermodynamically favorable.
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Answer:
6.208 mol
Explanation:
Mass of Bromine Liquid = 496g
Number of moles = ?
Relationship between number of moles and mass is given as;
Number of moles = Mass / Molar mass
Molar mass of Bromine = 79.9g
Number of moles = 496 / 79.9 = 6.208 mol
Carbon has 6 protons and boron only has 5
Besides nylon, HCl is formed from the reaction of adipoyl chloride and 1,6- diaminohexane , but HCl is the byproduct molecule.
<h3>What is formed when adipoyl chloride and 1,6-diaminohexane reacts with each other and what are the by products?</h3>
- Adipoyl chloride is the monomer and hexamethylinediamine is also the monomer which reacts together to form polymer.
- The polymer formed is named nylon6,6 which is a co polymer and nylon 6,6 find its use in various other activities of life.
- Nylon6,6 is a copolymer since the participation of two monomers , and not a single monomer undergoing decomposition.
- Nylon6,6 is formed with an elimination of small molecule of HCl which is considered to be a by product .
- It is formed by a condensation reaction and hence HCl is the product formed from the reaction of adipoyl chloride and 1,6- diaminohexane.
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Answer:
a) [H3O+] = 1.00 E-10 M ⇒ [OH-] = 1.0 E-4 M
b) [H3O+] = 1.00 E-4 M ⇒ [OH-] = 1.0 E-10 M
c) [H3O+] = 9.90 E-6 M ⇒ [OH-] = 1.0 E-9 M
Explanation:
- 14 = pH + pOH
- pH = - Log [H3O+]
a) [H3O+] = 1.00 E-10 M
⇒ pH = - Log(1.00 E-10) = 10
⇒ pOH = 14 - 10 = 4
⇒ 4 = - Log[OH-]
⇒ [OH-] = 1.0 E-4 M
b) [H3O+] = 1.00 E-4 M
⇒ pH = 4
⇒ pOH = 10
⇒ [OH-] = 1.0 E-10 M
c) [H3O+] = 9.90 E-6 M
⇒ pH = 5
⇒ pOH = 9
⇒ [OH-] = 1.0 E-9 M
