I am not completely sure about this one, but I found on the Internet that what is a condition required for the Hardy-Weinberg principle to be in effect is A) random mating occurs.
Answer:
The mechanisms of transport across the cell membrane are as follow: 1- simple diffusion, 2- facilitated diffusion, 3- primary active transport and 4-secondary active transport
Explanation:
The cell membrane is a selectively permeable structure capable of transporting substances by different mechanisms. Simple diffusion is a type of passive transport (i.e. does not require energy) where non-polar molecules (e.g. O2, CO2) pass across the membrane by a process that does not require energy from the cell. Facilitated diffusion is another type of passive transport where larger polar molecules (e.g., glucose and amino acids) pass across the membrane by using specific transmembrane integral proteins. On the other hand, primary active transport is a type of active transport that uses chemical energy (e.g., ATP) to move substances such as metal ions (Na+, K+, Ca2+) across the cell membrane against their concentration gradient. Finally, secondary active transport is another type of active transport where transporter proteins are used to couple the movement of ions (e.g., H+ protons) down their electrochemical gradient to the transport of another ions/solutes against their concentration/ electrochemical gradient.
Answer: Hello your question is incomplete below is the complete question
Let’s look at a different gene locus, we’ll call it B. The normal, wild type, the population was 100% BB. There are 150 Pakicetus in the population at present. Assume Charles had another mutation; this one at the B locus, to produce allele b. What is the gene frequency of allele b in the population if the population of Pakicetus reaches 100,000
answer : ≈ 1
Explanation:
<u>Determine the Gene frequency of allele b </u>
Population = 100,000
There are 150 Pakicetus in population i.e. 300 alleles at locus B
hence the frequency of b = 1/300 = 0.33%
Increase in population does not affect frequency of b ( HW equilibrium )
<em>therefore the Gene frequency of allele b </em>
= 0.33% * 0.33% * 100000 = 1.08
≈ 1
There are 23 pairs of chromosomes in each cell in a normal adult human.
Answer:
chickens
Explanation:
there are 25.9 billion of them