The first thing we must do for this case is to find the relationship between the variables.
We have then:
From here, we clear the value of "Y":
On the other hand we have:
From here, we clear the value of "x":
Then, replacing values we have:
On the other hand:
Finally, the perimeter is given by:
Substituting values we have:
Answer:
the perimeter of ABCD is:
44 units
Answer:
21^8
Step-by-step explanation:
YUUUUPPPPPP
Let the width be "x" cm.
Then the length is "x+12" cm
And the area = x(x+12) = x^2+12x cm^2
----------------------------
Change the dimensions:
width = "x-2" cm
length = "x+10" cm
New area = (x-2)(x+10) = x^2 + 8x - 20 cm^2
------------------
Equations :
Old area - New area = 108 cm^2
x^2+12x -(x^2 + 8x - 20) = 108
4x + 20 = 108
4x = 88
x = 22 cm (original width)
x+12 = 24 cm (original length)
Answer:
D= m/v. if D = 0.9 C.M m/720 = 648
<h2>X² + 2x = 4</h2><h2 />
When completing the square, the goal is to create
a perfect square trinomial on the left side of the equation.
The number used to create one will come from
half the coefficient of the middle term squared.
In this case, that's half of 2 squared or 1 squared, which is 1.
So we add 1 to both sides giving us x² + 2x + 1 = 5.
From here, we set this as a binomial squared.
The first term is an x and the second term will
be half the coefficient of the middle term squared.
So we have (x + 1)² = 5.
Now square root both sides and remember to use plus or minus.
So we have x + 1 = ±√5.
Now subtract 1 form both sides to get x = -1 ± √5.