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2 years ago

Select the two values of x that are roots of this equation. 2x2 + 7x + 6 = 0

1 answer:

3 0

Hopes this helps:

Answer: x = -10/7

1. Simplify 2 • 2 to 4
4 + 7x + 6 = 0

2. Simplify 4 + 7x + 6 to 7x + 10.
7x + 10 = 0

3. Subtract 10 from both sides.
7x = -10

4. Divide both sides by 7.
X = -10/7

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Sati [7]

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m=2 and n=3

Step-by-step explanation:

<u>Step</u> :-

Given $[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4$

using algebraic formula $(a^m)^n= a^{mn}$

now

$2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}$

now equating 'x' powers, we get

$x^{mn} = x^{6}$

$mn=6$ ....(1)

now

$y^{2m} = y^{4}$

Equating 'y' powers ,we get

2 m=4

m=2

substitute m= 2 in equation (1)

we get

2 n=6

n=3

verification:-

substitute m=2 and n=3 , we get

$[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4$

$(2 x^{3} y^2)^2 = 4 x^6 y ^4\\$

$4 x^6 y^4 = 4 x^6 y^4$

both are equating so m= 2 and n=3

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