<h2>
Answer:</h2>
We need to determine the equation of both lines first.
- Line 1: <em>y = -2x + 3</em>
- Line 2: <em>y = -1/3x - 2</em>
Now that we know the equations, we can set up a system of equations for this graph where both equations are in standard form.
Line 1:
Line 2:
<em>Final answer:</em>
Answer:
I think the figure of N and E of 48in is 2304. The figure of I and E and N and A of 32in is 1024. The figure of L and I and L and A is 144.
Step-by-step explanation:
To find the area, you have to multiply of each side in each figure. For example, Figure A and B and C and D of 16in is 16 × 16 which is 256.
A = Area
a = Side
A = 2304, A = a^2 = 48^2 = 2304.
A = 1024, A = a^2 = 32^2 = 1024.
A = 144, A = a^2 = 12^2 = 144.
I hope this answers your question!
Answer:
m∠QRS = 52°
Step-by-step explanation:
From the given figure,
In right triangles ΔRQT and ΔRST,
QT = TS = 7.5 units [Given]
RT ≅ RT [Reflexive property]
ΔRQT ≅ ΔRST [By HL theorem of congruence]
Therefore, m(∠QRT) = m(∠SRT) = 26° [CPCTC]
m(∠QRS) = 2m(∠QRT)
= 2×(26°)
= 52°
