Answer:
B. 192.5 ft³
Step-by-step explanation:
To find the volume of a triangle prism, multiply the base, height, and length together, and then divide it by 2 (or multiply that by 0.5).
(5 * 7 * 11)/2
Multiply 5 by 7 to get 35.
(35 * 11)/2
Multiply 35 by 11 to get 385.
385/2
192.5 ft³ is the volume of this triangluar prism.
Answer:
r≥0
V(r) ≥0
Step-by-step explanation:
V(r) = 4/3 * Pi* r^3
The domain is the input values for r
The radius cannot be less than 0 but can be any number bigger than 0
What is the domain of the function in this situation?
r≥0
The range is the output values for the function or the volume
The volume must be greater than or equal to zero
V(r) ≥0
x + y = 24 where x and y are the 2 parts of diagonal Other diagonal wil be smaller that 24.
x^2 + z^2 = 13^2
y^2 + z^2 = 20^2 where z = 0.5 * length of smaller diagonal)
form last 2 equations
y^2 - x^2 = 20^2 - 13^2 = 231
now y = 24-x so we have
(24 - x)^2 - x^2 = 231
576 - 48x = 231
48x = 345
x = 7.1875
z^2 = 13^2 - 7.1875^2 = 117.34
z = 1.83
so smaller diagonal = 21.66 cm
looks like its the third choice.
9514 1404 393
Answer:
x = 2√2 ≈ 2.83
Step-by-step explanation:
The side length of an isosceles right triangle is 1/√2 times the hypotenuse length. If x is the side length, then ...
x = 4/√2 = 4(√2)/2
x = 2√2 ≈ 2.83
__
You have not specified the form of the answer. Sometimes an exact answer (2√2) is required. Sometimes the answer is required to be rounded to tenths or hundredths.
Answer:
B
Step-by-step explanation:
The interquartile range is the difference between the upper quartile and the lower quartile.
The upper quartile is the right side value of the box
The lower quartile is the left side value of the box
upper quartile = 61 and lower quartile = 39
IQR = 61 - 39 = 22 → B
