Graph the following state and show the a h and k values. y=2(x+3)^2-4
1 answer:
This equation is in vertex form. Vertex form is y=a(x-h)^2+k, where (h,k) is the vertex. In this equation, h= -3, and k= -4. So, the vertex would be at (-3,-4). A tells us if the parabola will be positive or negative. In this case, it is positive, so the parabola opens upward. Then, you can solve for x-intercept by letting y=0 and solving for x. Then, you can find the y-intercept by setting x=0 and solving for y. Finally, graph the parabola.
You might be interested in
