The x-y coordinates for the given equation are: (-2,11),(-1,7),(0,3), (1,-1) and (2,-5).
<h3>Linear Function</h3>
A linear function can be represented by a line. The standard form for this equation is: ax+b , for example, y=2x+7. Where:
- a= the slope;
- b=the constant term that represents the y-intercept.
The given equation is 16x + 4y = 12. For solving this question, you should replace the given values of x for finding the values of y.
Thus,
- For x= -2, the value of y will be:
16*(-2)+4y=12
-32+4y=12
4y=12+32
4y=44
y=11
- For x= -1, the value of y will be:
16*(-1)+4y=12
- -16+4y=12
- 4y=12+16
- 4y=28
- y=7
- For x= 0, the value of y will be:
16*(0)+4y=12
- For x= 1, the value of y will be:
16*(1)+4y=12
- 16+4y=12
- 4y=12-16
- 4y=-4
- y= -1
- For x= 2, the value of y will be:
16*(2)+4y=12
- 32+4y=12
- 4y=12-32
- 4y=-20
- y= -5
Read more about the linear equation here:
brainly.com/question/1884491
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Answer:
{0.16807, 0.36015, 0.3087, 0.1323, 0.02835, 0.00243}
Step-by-step explanation:
The expansion of (p+q)^n for n = 5 is ...
(p+q)^5 = p^5 +5·p^4·q +10·p^3·q^2 +10·p^2·q^3 +5·p·q^4 +q^5
When the probability p=0.3 and q = 1-p = 0.7 the terms of this series correspond to the probabilities of 5, 4, 3, 2, 1, and 0 favorable outcomes out of 5 trials.
For example, p^5 = 0.3^5 = 0.00243 is the probability of 5 favorable outcomes in 5 trials where the probability of each favorable outcome is 0.3.
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The attachment shows the calculation of these numbers using a graphing calculator. It lists them in reverse order of the expansion of (p+q)^5 shown above, so that they are the probabilities of 0–5 favorable outcomes in the order 0–5.
Answer:
L(0,0)
M(2,4)
N(4,2)