After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.
Step-by-step explanation:
You can find the amount of students each vehicle can carry by representing the two scenarios in equations.
You are trying to find how many students will fit in each bus or van, so the two variables used will be "b" to represent how many students can fit in a bus and "v" to represent how many students can fit in a van.
High school A used 1 van and 6 buses, so there will be 1"v" and 6"b" for 372 students.
High school B used 4 vans and 12 buses, so there will be 4"v" and 12"b" for 780 students.
Now, represent these in equations:
We can use substitution to solve this system:
can be rewritten as 
after subtracting 6b from both sides. You can then substitute this new value of "v" into the other equation to solve for "b":
After solving for b, you can then substitute the new value of b into the other equation to find the value of v:
After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.
<span>x = 2, y = 1
= 3*2 + 7*1
= 6+7
= 13
Hence, (2, 1) is the answer.</span>
<span>y^2 + 5y + 6
=</span><span>(y + 2)(y + 3)
----------------------------------</span>
Step-by-step explanation:
The system of equations for eq 1 which is 3x + y = 118 represents the Green High School which filled three buses(with a specific number of students identified as x) and a van(with a specific number of students identified as y) with a total of 118 students.
for eq 2; 4x + 2y = 164; represents Belle High School which filled four buses(with a specific number of students identified as x) and two vans(with a specific number of students identified as y) with a total of 164 students.
The solution represents the specific number of students in the buses and vans in eq1 and eq 2 with x being 36 students and y being 10 students.
substituting 36 for x and 10 for y in eq 1;
3(36) + 10 = 108 + 10 = 118 total students for Green High School
substituting 36 for x and 10 for y in eq2;
4(36) + 2(10) = 144 + 20 = 164 total students for Belle High school
Answer:
He must sell 1390 carrots
Step-by-step explanation:
30x + 300x/30 = 55500
40x = 55500
x = 1387.5
1387.5
multiply 30 by .3 to get $9 for 30 carrots
Then add $3 to this amount to get $12 dollars.
Divide 555 by 12 to get 46 R3.
Multiply 46 by 30 because its 46 bundles of 30 carrots
Then divide the 3 dollars by .3 for each carrot to get 10 carrots
1380+10 = 1390
