Answer:
Step-by-step explanation:
(x−a)(x−b)=x2−(a+b)x+ab
Now, this with the third bracket.
(x2−(a+b)x+ab)(x−c)=x3−(a+b+c)x2+(ac+bc+ab)x−abc
But there’s another way to do this, which is easier. Assume the given expression is equal to 0, then, we can form a cubic equation as
x3−(sum−of−roots)x2+(product−of−roots−taken−two−at−a−time)x−(product−of−roots) , which is essentially what we got above.
