More people walk to school or work hope this helps
Answer:
Options A and D
Explanation:
In this question the student needs to collect these measurements in order to approximate the work done
A. The mass of the student
D. The final vertical height above the initial vertical position.
Workdone = mgh
m = mass
g = gravity = 9.8m/s²
h = vertical height between the initial and the final positions.
The vertical height has to be known as gravity only acts straight down.
Answer:
v = 7.67 m/s for L= 1m
Explanation:
Let's use the conservation of mechanical energy, at the highest point and the lowest point
Initial. Vertical ruler
Em₀ = mg h
Final. Just before touching the floor
= K = ½ I w²
Em₀ =
m g h = ½ I w²
The moment of inertia of a ruler that turns on one end is
I = 1/3 m L²
Let's replace
m g h = ½ (1/3 m L²) w²2
g h = 1/6 L² w²
They ask for the speed of the end so the height h is equal to the length of the ruler
g L = 1/6 L² w²
The linear and angular variables are related
v = w r
w = v / r
In this case the point of interest a in strangers r = L
g L = 1/6 L² v² / L²
v = √ 6 g L
Let's calculate
Assume that the length of the meter is L = 1 m
v = √ (6 9.8 1)
v = 7.67 m/s
What the equation given?
- x(t)=Acost
Maximum velocity occurs at the equilibrium position
So
Now
Now
As we know the formula
These expressions can be used