See the attached figure to better understand the problem
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid
we know that
One edge of the cuboid has length 2 cm-----> <span>I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1
[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]
100=</span>2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm
<span>Find the length of a diagonal of the cuboid
</span>diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm
the answer is the length of a diagonal of the cuboid is 13.75 cm
Answer:
X=-2
Y=-6
Step-by-step explanation:
Since both equations are already expressed in the simplest form of y, then we equate them to be equal hence
x-4=4x+2
Bringing like terms together
-4-2=4x-x
Solving both sides
-6=3x
Making x the subject then
X=-6/3=-2
Subsrituting the value of x into any of the initial equations
Y=x-4 then y=-2-4=-6
Therefore, the solution is
X=-2
Y=-6
Answer:
It is B the right triangle altitude theorem
Step-by-step explanation:
edg. 2021
Step-by-step explanation:
there are 50 students and 5 prizes (1 + 1 + 3).
so, already in natural language we would say "there is 1 prize for every 10 students".
formally, remember the rule of probability : desired outcomes over total possible outcomes.
this is here
5/50 = 1/10 = 0.1
your can see it also this way :
if there was only 1 prize, each student would have a chance of 1/50 of winning.
now there are 5 prizes, which gives everybody 5 times the chance of winning. which is then 5×1/50 = 5/50 = 0.1