The lengths of the sides of the triangle are 8, 8, 20
Explanation:
Given that the perimeter of an isosceles triangle is 36 inches.
The base of the triangle is times longer than each of its legs.
We need to determine the lengths of the sides of the triangle.
<u>Lengths of the sides:</u>
Let x denote the lengths of the sides of the triangle.
The base of the triangle is given by
Perimeter of the isosceles triangle = Sum of the three sides of the triangle.
Thus, we have,
Thus, the length of the sides of the isosceles triangle is 8 inches.
Base of the triangle =
Hence, the three sides of the isosceles triangle are 8, 8, 20
5√2 · 9√6
Simplify.
5 × 9 √ 2 x 6 ⇒ Multiply 2 × 6.
5 × 9 √12
Simplify √12 to 2√3.
5 × 9 × 2√3 ⇔ Multiply
90√3
Therefore, the <u>correct alternative</u> is <u>option "B".</u>
I will answer in just a second I’m showing work
I think it's B. 168 units
Because I multiplied them all together and halved the answer
Answer:
Option D, x = 4
Step-by-step explanation:
Option A: y = 4 doesn't work because that line would be horizontal
Option B: y = 4x doesn't work because that would be diagnol
Option C: x = -4 doesn't work because that would a vertical line at -4
<em>Option D: x = 4 works because that would a vertical line at 4</em>
<em />
Answer: Option D, x = 4