x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
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Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
Answer:
chicken and chicken
Step-by-step explanation:
just took the test
R(x) is a polynomial. Thus, the domain is the same as the range.
Domain = range = ALL REAL NUMBERS.
We can also express the answer as
(-infinity, infinity).
<span>Ratio students to classroom in school A equals 216:12 which simplifies to 18:1. Ratio students to classroom in school B equals 104:4 which simplifies to 26:1.Total students combining school A and B equals 216+104=320 and Total classroom 12+4=16, if both school combined are assumed to be a single school C, than ratio of of students to the classroom in school C equals 320:16 which simplifies to 20:1 which means 20 students in every classroom, now total students in 4 classroom of School C equals 20x4=80, these 4 classroom are separated as School B and other 12 classroom School A, now ratio still 20:1 (same in both schools).
initially students in School B were 104 and now are 80, then total students transferred equals 104-80= 24.</span>