A standard cube has 6 possible outcomes. But since we want to find P(4+ or odd), the outcomes become more narrow.
So:
6 outcomes -> 1, 2, 3, 4, 5, 6
But we want to find 4+
So:
4+ = 4, 5, 6
We also want to find all odd possibilities.
So:
odd = 1, 3, 5
As you can see, there is a 5 in both the 4+ and the odd numbers so 5 will only be counted once.
P(4+ or odd) = 1, 3, 4, 5, 6
So the probability of having an outcome that is P(4+ or odd) is:
5/6 or 0.8333 or 83.33%
Hope I helped!
Answer:
17. a)
Step-by-step explanation:
17.
f(x) =x/2, then f(x-3)=(x-3)/2
x=3, f(x-3)=f(3-3)=f(0)=0 (values in table)
f(x-3)+3=0+3=3
18.
f(x) =x/2
f(x-2) for x=5 is f(5-2)=f(3)=3/2
f(x-2)+5=f(3)+5=3/2+5=3/2+10/2=13/2
Answer:
4) m: 1.25 b: 6 Equation: y= 1.25x + 6
5) m: 20 b: 10 Equation: y= 40x + 10
6) m: -2 b: 0 Equation: y= -2x + 0
7) m: 1/5 b: 1 Equation: y= 1/5x + 1
8) -8.7 = 1.3x + 0
I really hope this helps!
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