Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is
Hence, the average of the shortest distance of B from each side is 22 m
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-7(2)+y=60
-14+y=60
y=60+14
Y=74
Answer:
2.33
Step-by-step explanation:
Plug "7/3" in your calculator and round to the nearest hundredth (by finding the hundredth's place, looking at the digit before it, and moving the hundredth's place up one value if you deciphering that the digit before is greater/equal to 5). If you need a terminating decimal, you need to round. If you don't need it as a terminating decimal, add a ling over the last digit where the decimal begins to repeat.
Answer: Square root of 200= 14.14ft
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